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Coupling selection case calculation

2022-02-13|admin


There are usually two ways to choose a coupling:


Select a suitable coupling according to the maximum torque, i.e. the peak torque required by the load should not exceed the rated torque of the coupling:


TKN ≧ 1.5 TAS Nm


The coupling is selected according to the acceleration torque. At this time, the rotational inertia of the drive system needs to be considered. If the inertia ratio is large, the influence of the load factor in the calculation of the coupling specification will be reduced:


联轴器负载系数计算.png

振动或负载系数 SA

均匀载荷

非均匀载荷

高动态载荷

1

2

3-4

对伺服电机来说,负载系数通常为SA=2-3

 

Calculation example:


Servo motor drive, maximum torque TAS=50Nm


Load factor SA=3


联轴器选型计算.png

So 联轴器选型计算公式.pngIt can be seen that when the load inertia is relatively large, the inertia of the coupling itself has little influence on the calculation results.


In addition to the torque, it is necessary to consider whether the speed meets the requirements. Most of the R+W couplings have been preliminarily balanced before leaving the factory. The default speed of some smaller models can reach 10000rpm. If the equipment needs The rotation speed is relatively high, and additional dynamic balancing treatment is required.


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